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Q.

An air bubble doubles its radius on raising from bottom to the surface of water reservoir. If the atmospheric pressure is equal to 10 m of water. Then the height of water in the reservoir is( Assume the temperature to be constant)

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a

20 m

b

70 m

c

10 m

d

80 m

answer is C.

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Detailed Solution

According to Boyle’s law

${(P_{1} V_{1})}_{b o t t o m} = {(P_{2} V_{2})}_{T o p}$

$(10 + h) \times r^{3} = 10 \times 8 r^{3}$

$∴ h = 70 m$

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