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An air bubble in a glass slab with refractive index 1.5 (near normal incidence) is 6 cm deep when viewed from one surface and 4 cm deep when viewed from the opposite face. The thickness (in cm ) of the slab is:

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answer is C.

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Detailed Solution

Here $μ$ =1.5

l= length of the slab

x= position of air bubble from one side As per question,

total apparent length of slab= 6 + 4 = 10 cm

$\begin{array}{l} or, \frac{x}{μ} + \frac{(l - x)}{μ} = 10 or, \frac{l}{μ} = 10 \\ ∴ l = 10 μ = 10 \times 1.5 = 15 cm \end{array}$

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