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An air bubble in sphere having 4 cm diameter appears 1 cm from surface nearest to eye when looked along diameter. If $_{α} μ_{g} = 1.5$ , the distance of bubble from refracting surface is

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1.6 cm

1.2 cm

2.8 cm

3.2 cm

answer is A.

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Detailed Solution

$\frac{μ_{a}}{v} - \frac{μ_{g}}{u} = \frac{μ_{a} - μ_{g}}{R}$

here

$\begin{aligned} v = 1 cm \\ R = 2 cm \end{aligned}$

$\frac{1}{- 1} - \frac{1.5}{μ} = \frac{1 - 1.5}{- 2} = 1.2 cm$

$μ = 1.2 cm$

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