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An air bubble is at a depth h below the free surface of water. If pressure inside the bubble is three times that of atmospheric pressure ( $P_{0}$ ). The radius of the bubble is given by [ $ρ$ = density of water, T = surface tension]

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$\frac{3 T}{P_{0} - ρ g h}$

$\frac{2 T}{P_{0} - 2 ρ g h}$

$\frac{3 T}{3 P_{0} - 2 ρ g h}$

$\frac{2 T}{2 P_{0} - ρ g h}$

answer is D.

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Detailed Solution

$P_{o} + h ρ g + \frac{2 T}{R} = 3 P_{0}$

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