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An air bubble is located at a distance of 4cm from the centre of the sphere of radius 6cm and refractive index 1.5. Locate its image when viewed through a surface closer to bubble.

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1.5 cm from the centre

4.5 cm from centre

2 cm from centre

3 cm from the centre

answer is B.

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Detailed Solution

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$\begin{array}{l} \frac{μ_{2}}{V} - \frac{μ_{1}}{u} = (\frac{μ_{2} - μ_{1}}{R}) \\ \frac{1}{V} - \frac{1.5}{- 2} = \frac{1 - 1.5}{- 6} \Rightarrow V = 1.5 cm \end{array}$
$∴$ from centre 4.5 cm

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