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An air bubble of diameter 0.8mm rise in a liquid of viscosity 0.15 $N s / m^{2}$ and specific gravity 0.9. Find magnitude of terminal velocity of bubble. Density of air is 1.293 $k g / m^{3}$ .

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0.21 cm/s

0.38 cm/s

0.52 cm/s

0.68 cm/s

answer is C.

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Detailed Solution

$v_{t} = \frac{2}{9} \frac{r^{2} g (ρ - σ)}{η} r = 0.4 m m = 4 \times 10^{- 4} m ρ = 0.9 \times 10^{3} k g / m^{3} v_{t} = \frac{2}{9} \frac{16 \times 10^{- 8} \times 10 (900 - 1.293)}{15 \times 10^{- 2}} \approx 0.21 c m / s$

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