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Q.

An air bubble of radius 0.1 cm lies at a depth of 20 cm below the free surface of a liquid of density 1000 kg/m3. If the pressure inside the bubble is 2100 N/m2 greater than the atmospheric pressure, then the surface tension of the liquid in SI unit is (use g = 10 m/s2)

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a

0.02

b

0.1

c

 0.25

d

0.05

answer is D.

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Detailed Solution

T is surface tension
Pin air bubble=P0+ρgh+2TR
 Pin−P0=ρgh+2TR=2100 2TR=2100−ρgh T=R2(2100−103×10×0.2) =120(2100−2000)×10−2 =0.05

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