An air bubble of radius 0.1cm is in a liquid having surface tension 0.06 N/m and density 10³kg /m³. The pressure inside the bubble is 1100 Nm^-2 greater than the atmospheric pressure. At what depth is the bubble below the surface of the liquid? (g = 9.8 ms^-2)

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0.15m

0.20m

0.25m

0.1m

answer is A.

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Detailed Solution

As we know,
$\begin{array}{l} p_{excess} = hρg + \frac{2 s}{r} \\ \Rightarrow 1100 = h \times 10^{3} \times 9 .8 + \frac{2 \times 6 \times 10^{- 2}}{10^{- 3}} \\ \Rightarrow h = \frac{980}{9800} = 0 .1 m \end{array}$

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