An air bubble of radius 1.0 mm is observed at a depth of 20 cm below the free surface of a liquid having surface tension 0.095 J/m2 and density 103 kg/m3. The difference between pressure inside the bubble and atmospheric pressure______ N/m2. (Take g = 10 m/s2)

∆P = Pin – P0=ρgh+2TR=1000×10×20100+2×0.09510−3= 2000 + 190= 2190

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An air bubble of radius 1.0 mm is observed at a depth of 20 cm below the free surface of a liquid having surface tension 0.095 J/m² and density 10³ kg/m³. The difference between pressure inside the bubble and atmospheric pressure______ N/m². (Take g = 10 m/s²)

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answer is 2190.

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$∆$ P = P_in – P₀
$= ρgh + \frac{2 T}{R} = \frac{1000 \times 10 \times 20}{100} + \frac{2 \times 0.095}{10^{- 3}}$
= 2000 + 190
= 2190

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