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An air bubble of radius 1 cm rises from the bottom portion through a liquid of density 1.5g/cc at constant speed of 0.25cm/sec. If the density of air is neglected the coefficient of viscosity of the liquid is approximately (In pa. s)

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13, 000

130

11300

answer is C.

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Detailed Solution

Given,

$radius r = 1 cm = 1 \times 10^{- 2} m$

$density = ρ = 1.5 \times 10^{3}$

$speed v = 0.25 \times 10^{- 2} m / s$

We know that the coefficient of viscosity =

$η = \frac{2}{9} {(1 \times 10^{- 2})}^{2} \times (1.5 \times 10^{3} \times 9.8) = 130 Pa / s$

Hence the correct answer is 130.

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