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An air bubble of radius 1 mm is formed inside water at a depth 10 m below free surface (where air pressure is $10^{5} N / m^{2}$ ). The pressure inside the bubble is (Surface tension of water $= 7 \times 10^{- 2} N / m$ )

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$2.28 \times 10^{- 5} N / m^{2}$

$2.0028 \times 10^{5} N / m^{2}$

$2.14 \times 10^{- 5} N / m^{2}$

$2.0014 \times 10^{5} N / m^{2}$

answer is D.

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Detailed Solution

$p = p_{0} + ρ g h + \frac{2 T}{r}$

$(10^{5}) + (10^{3}) (10) (10) + \frac{2 \times 7 \times 10^{- 2}}{10^{- 3}}$

$= 2.0014 \times 10^{5} N / m^{2}$

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