An air bubble of radius 1 mm is formed inside water at a depth 10 m below the surface of water. The pressure inside the bubble is (Surface Tension of water $7 \times 10^{- 2} N m^{- 1};$ atmospheric pressure = $10^{5} N m^{- 2}$ and $g = 10 m s^{- 2}$ )

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

$2.0014 \times 10^{5} N m^{- 2}$

$2.0028 \times 10^{5} N m^{- 2}$

$2.28 \times 10^{5} N m^{- 2}$

$2.14 \times 10^{5} N m^{- 2}$

answer is D.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Pressure inside the bubble inside water

$P_{0} + h d g + \frac{2 T}{r} = 2 \times 10^{5} + \frac{2 \times 7 \times 10^{- 2}}{10^{- 3}} = 2 \times 10^{5} + 14 \times 10$

=2.0014 $\times 10^{5}$ N/m²

Watch 3-min video & get full concept clarity

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test