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An air compressor is powered by a 200 rad/s electric motor using a V-belt drive. The motor pulley is 8cm in radius, and the tension in the V-belt is 135N on one side and 45N on the other. The power of the motor will be

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14.4 kW

28.8 kW

1.44 kW

2.88 kW

answer is A.

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Detailed Solution

$τ = R (F_{1} - F_{2}) = 8 \times 10^{- 2} \times 90 N - m P = τ ω = 8 \times 10^{- 2} \times 90 \times 200 w a t t = 1440 = 1.44 k w$

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