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Q.

An air fileld ballon floats in water with half of its volume submerged. To what depth inside water should it be taken so that it remains in equilibrium there? Take atmospheric pressure to be equal to 10 m of water height.

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a

15 m

b

10 m

c

20 m

d

5m

answer is B.

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Detailed Solution

Mass of balloon =V02×1
From Boyle’s law, 
PV=P0V0
Mass of balloon remains unchanged,
 V02×1=V×1⇒V=V02P=2P0=20m of water ∴ Required depth =10m

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