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An aircraft flies at 400km/h in still air. A wind of $200 \sqrt{2}$ km/h is blowing from the south.
The pilot whishes to travel from A to a point B. north of east of A
Match the statements in column I with corresponding results in Column II
Column I Column II
A The direction he must steer the aircraft from AB line is (in degree) p 1.83
B Time of journey if AB = 1000 km (in hr) q 30
C Time journey if AB = 546.47 KM(in hr) r 15
D Direction of $\vec{V a w}$ from the east (in degree) is s 1

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$A \to q; B \to p; C \to s; D \to r$

$A \to p; B \to r; C \to s; D \to q$

$A \to r; B \to q; C \to p; D \to s$

$A \to q; B \to r; C \to s; D \to p$

answer is A.

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Detailed Solution

$V_{w} \sin 45^{0} = V_{a w} \sin θ t = \frac{A B}{V_{w} \cos 45 + V_{a w} \cos θ}$

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