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An aircraft with a wingspan of 40 m flies with a speed of $1080 kmph$ in the eastward direction at a constant altitude in the northern hemisphere, where the vertical component of earth's magnetic field is $1.75 \times 10^{- 5} T$ . Then the emf that develops between the tips of the wings is

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0.5 V

0.21 V

2.1 V

0.35 V

answer is C.

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Detailed Solution

L= 40 m, v =1080b km $h^{- 1}$ = 300 m / s and B =1.75 x $10^{- 5}$ T

\Rightarrow e = Bl\,v = 1.75 \times {10^{ - 5}} \times 40 \times 300 = 0.21\,V

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