An airplane pilot wants to fly from city A to city B which is 1000 km due north of city A. The speed of the plane in still air is 500 km/hr. The pilot neglects the effect of the wind and directs his plane due north and 2 hours later find himself 300km due north-east of city B. The wind velocity is

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106km/hr at 45°N of E

106 km/hr at 45°N of W

150km/hr at 45°N of E

150 km/hr at 45°N of W

answer is A.

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Detailed Solution

$\begin{array}{l} \frac{300}{1000} = \frac{v_{ω}}{500} \\ v_{ω} = 150 k m h r^{- 1} 45 º N o f E a s t_{} \end{array}$

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