Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8

Q.

An alcohol (A) on treatment with conc.H2SO4 gave an alkene (B). The compound (B), on reacting with Br2 water and subsequent dehydrobromination with NaNH2produced a compound (C). The compound (C) with  dil.H2SO4 in presence of HgSO4 gave a compound 'D'. The compound D can also be obtained by oxidation of A by acidified KMnO4 or from dry heating of calcium acetate. Calculate molecular weight of 'C'

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Question Image

 

Question Image

 

Question Image

 

Question Image

 

The molecular weight of 'C'(C3H4) is 36+4=40 g/mol

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
An alcohol (A) on treatment with conc.H2SO4 gave an alkene (B). The compound (B), on reacting with Br2 water and subsequent dehydrobromination with NaNH2produced a compound (C). The compound (C) with  dil.H2SO4 in presence of HgSO4 gave a compound 'D'. The compound D can also be obtained by oxidation of A by acidified KMnO4 or from dry heating of calcium acetate. Calculate molecular weight of 'C'.