An alcohol contains 60% carbon and 13.3% hydrogen and gives positive iodoform test. The alcohol is

$\mathrm{C}:\mathrm{H}:\mathrm{O}=\frac{60}{12}:\frac{13.3}{1}:\frac{26.7}{16}=\frac{5}{1.67}:\frac{13.3}{1.67}:\frac{1.67}{1.67}=3:8:1$

The formula of the compound is C₃H₈O.
Since the alcohol gives positive iodoform test. It has 

CH₃CH(OH)CH₃

hence it is 2-propanol.