An alcohol on oxidation gives ${CH}_{3} COOH$ and ${CH}_{3} {CH}_{2} COOH .$ The alcohol is

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$\begin{aligned} {CH}_{3} CH (OH) {CH}_{2} {CH}_{2} {CH}_{3} \end{aligned}$

$\begin{aligned} {CH}_{3} {CH}_{2} {CH}_{2} OH \end{aligned}$

$\begin{aligned} {CH}_{3} CH (OH) {CH}_{2} {CH}_{3} \end{aligned}$

${({CH}_{3})}_{2} C (OH) {CH}_{2} {CH}_{3}$

answer is D.

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Detailed Solution

The alcohol is secondary alcohol and will have 5 C atoms because oxidation of secondary alcohol produces the two distinct acids acetic acid and propanoic acid.

${CH}_{3} CH (OH) {CH}_{2} {CH}_{2} {CH}_{3} \overset{oxidation,extreme condition}{⟶} {CH}_{3} COOH + {CH}_{3} {CH}_{2} COOH$

Hence option D is correct

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