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Q.

An alkaloid contains 17.28% of nitrogen and its molecular mass is 162. The number of nitrogen atoms present in one molecule of the alkaloid is

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a

Five

b

Four

c

Three

d

Two

answer is D.

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Detailed Solution

% of element = $\frac{No . of atoms \times at . wt}{Molar mass of compounds} \times 100$

$17.28 = \frac{x \times 14}{162} \times 100$

$x = \frac{17.28 \times 1, 62}{14} = \frac{28}{14} = 2$

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