An alkene ‘A’ on reaction with O₃ and $Z n - H_{2} O$ gives propanone and ethanal. Addition of HCl to alkene gives (B) as the major product. The structure of product B is

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$H_{3} C - {CH}_{2} - CH ({CH}_{2} Cl) - {CH}_{3}$

${CH}_{3} - CH (Cl) - CH {({CH}_{3})}_{2}$

$Cl - {CH}_{2} - {CH}_{2} - CH {({CH}_{3})}_{2}$

$H_{3} C - {CH}_{2} - C ({CH}_{3}) (Cl) - {CH}_{3}$

answer is D.

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Detailed Solution

2) $\overset{H_{3} O^{+}}{\to} C H_{3} - \underset{\overset{|}{O H}}{\overset{\underset{|}{C H_{3}}}{C}} - \overset{C H_{3}}{\overset{|}{C}} H - C H_{3}$

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