An alkene (A) C₁₆H₁₆ on Ozonolysis gives only one product (B)C₈H₈O . Compound (B) on reaction with NaOH/I₂ yields sodium benzoate. Compound (B) reacts with KOH/NH₂−NH₂ yielding a hydrocarbon(C) C₈H₁₀. Write the structure of (B) and based on this information the no. of isomeric structures of (A) will be

Analysis of Alkene (A) and Its Products

Given that alkene (A) has the formula C₁₆H₁₆ and upon ozonolysis yields compound (B) with the formula C₈H₈O, we can deduce that compound (B) is likely a ketone or an aldehyde. The ozonolysis of alkenes typically results in carbonyl compounds, and since (B) reacts with NaOH/I₂ to yield sodium benzoate, it suggests that (B) is benzaldehyde or a derivative.

The structure of compound (B), which is C₈H₈O, can be represented as follows:

When compound (B) reacts with KOH/NH₂-NH₂, it forms a hydrocarbon (C) with the formula C₈H₁₀. This indicates that a reduction occurs, likely converting benzaldehyde to styrene or another similar hydrocarbon.

Since alkene (A) has the formula C₁₆H₁₆, it can have multiple structural isomers. The number of isomeric structures depends on various factors such as:

• The position of double bonds
• The arrangement of substituents
• The presence of rings

For alkenes with this formula, there could be numerous structural isomers due to the potential for branching and different configurations around the double bond.