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Q.

An alkene on treating with hot acidified ${KMnO}_{4}$ gives propanoic acid and acetic acid. The alkene is

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a

${CH}_{3} CH = {CHCH}_{3}$

b

${({CH}_{3})}_{2} C = {CH}_{2}$

c

$H_{3} C - {CH}_{2} - CH = CH - {CH}_{3}$

d

${CH}_{3} CH = {CH}_{2}$

answer is B.

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Detailed Solution

$H_{3} C - {CH}_{2} - CH = CH - {CH}_{3} \to_{H^{+}}^{{KMnO}_{4}}$
$H_{3} C - {CH}_{2} - COOH + {CH}_{3} COOH$

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An alkene on treating with hot acidified KMnO4 gives propanoic acid and acetic acid. The alkene is