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Q.

An alkyl bromide reacts with sodium to form 4, 5-diethyloctane. The alkyl bromide is

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a

CH3(CH2)2CHBrCH2CH3

b

CH3(CH2)4CH2Br

c

CH3(CH2)3CHBrCH3

d

CH3(CH2)2CH2Br

answer is D.

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Detailed Solution

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CH3(CH2)2CHBrCH2CH3

R−X→Na/ etherR−R

so given alkane divided by half and gets corresponding alkyl halide as following:

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