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Q.

An alpha nucleus of energy 1/2 mv²bombards a heavy nuclear target of charge Ze. Then the distance of closet approach for the alpha nucleus will the proportional to:

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a

$\frac{1}{ϑ}$

b

1/m

c

1/Ze

d

$ϑ^{2}$

answer is D.

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Detailed Solution

$E = \frac{1}{2} {mv}^{2} = \frac{1}{4 {πϵ}_{o}} \cdot \frac{2 {ze}^{2}}{r_{o}}; ∴ r_{0} \propto \frac{1}{m}$

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An alpha nucleus of energy 1/2 mv2 bombards a heavy nuclear target of charge Ze. Then the distance of closet approach for the alpha nucleus will the proportional to: