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Q.

An alpha nucleus of energy 12mv2 bombards a heavy nuclear target of charge Ze. The distance of closest approach for the alpha nucleus will be proportional to

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a

1m

b

1Ze

c

1v4

d

v2

answer is D.

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Detailed Solution

 As, KE=P.E ⇒12mv2=k(2e)(Ze)r0

⇒r0=4kZe2mv2

∴r0∝1m

[ The distance of closest approach r0, m = mass alpha particle ]

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