An alpha particle is projected vertically upward with a speed of $3.0 \times 10^{4} km/s$ in a region where a magnetic field of magnitude 1.0 T exists in the direction South of North. The magnetic force that acts on the $α$ particle is

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$9.6 \times 10^{- 12} N towards West$

$9.6 \times 10^{- 12} N towards North$

$9.6 \times 10^{- 12} N towards South$

$9.6 \times 10^{- 6} N towards East$

answer is B.

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Detailed Solution

$v = 3 \times 10^{4} \times 10^{3} m/s B = 1T q_{d} = 2 \times 1.6 \times 10^{- 19} c F = {Bq}_{d} v F = (1) \times 2 \times 1.6 \times 10^{- 19} \times 3 \times 10^{4} \times 10^{3} F = 9.6 \times 10^{- 12} N towards west$

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