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Q.

An alternating current is given by $i = (3 \sin ω t + 4 \cos ω t) A$ . The rms current will be

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a

$\frac{1}{\sqrt{2}} A$

b

$\frac{7}{\sqrt{2}} A$

c

$5 A$

d

$\frac{5}{\sqrt{2}} A$

answer is C.

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Detailed Solution

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$i = 5 \sin (ω t + \tan^{- 1} (\frac{4}{3}))$

$i_{0} = 5 A ∴ i_{rms} = \frac{i_{o}}{\sqrt{2}} = \frac{5}{\sqrt{2}} A$

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