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An alternating emf of 200V and 50 cycles per second is connected to a circuit of resistance $3.14 Ω$ and inductance 0.01H. The lag in time between the emf and the current is

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4.5 ms

2.5 ms

1.5 ms

3.5 ms

answer is B.

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Detailed Solution

$T a n θ = \frac{X_{L}}{R} = 1$

$θ = 45^{0} = \frac{π}{4}$

$t = θ \times \frac{t i m e p e r i o d}{2 π} = \frac{π}{4} \times \frac{1}{50} \times \frac{1}{2 π}$

$= \frac{1}{400} = 2.5 m s$

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