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Q.

An aluminium wire is stretched to make its length, 0.4% larger. The percentage change is resistance is

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a

0.2%

b

0.6%

c

0.4%

d

0.8%

answer is C.

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Detailed Solution

$\begin{array}{l} R = \frac{ρ l^{2}}{v} \\ R α l^{2} \\ \frac{Δ R}{R} \times 100 = 2 \frac{Δ l}{l} \times 100 \\ = 2 (0.4) = 0.8 % \end{array}$

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