An aluminum square sheet of negligible thickness has dimensions 90 cm × 90 cm. From each corner, a square of side 24 cm is cut out to form an open container. What is the maximum amount of water that the container can hold?

[1 L = 1000 cm³]

Length of aluminum sheet = 90 cm

Length of side of the square that is cut from each corner = 24 cm

∴ Length of the container = [90 – (24 + 24)] cm = 42 cm

Breadth of the container = [90 – (24 + 24)] cm = 42 cm

Height of the container = 24 cm

Thus, the container so formed is in cuboidal shape whose volume is given by (length ×breadth ×height).

Volume of the container = Length × Breadth × Height

= (42 ×42 ×24) cm³

= 42336 cm³

1 L = 1000 cm³

Thus, the maximum amount of water that the container can hold is, $\frac{42336}{1000}=42.336 \mathrm{L}$.