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An ammeter reads up to 1 ampere. Its internal resistance is 0.81 ohm. To increase the range to 10 A, the value of the required shunt is

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$0 .3 Ω$

$0 .09 Ω$

$0 .03 Ω$

$0 .9 Ω$

answer is A.

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Detailed Solution

$\frac{i}{i_{g}} = 1 + \frac{G}{S} \Rightarrow \frac{10}{1} = 1 + \frac{0 .81}{S} \Rightarrow S = 0 .09 Ω$

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