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Q.

An amount of 1 mole of a non volatile binary electrolyte AB is dissolved in 100 moles of water. This solution has freezing point 271.5 K. Identify the correct informations ( Kf of water= 1.8K.kg.mol1, freezing temperature of pure water is 273 K, degree of ionization of AB remain same at all temperatures)

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a

The degree of dissociation of AB is 0.5

b

If the solution is cooled up to -2°C then nearly 450 g of ice separated from the solution

c

If vapour pressure of pure water at 373 K is 760 mm of Hg then vapour pressure of given solution is 752.4 mm of Hg at same temperature

d

The ratio of normal molar mass to abnormal molar mass of AB is 1.5

answer is A, B, D.

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Detailed Solution

(273271.5)=(1.8)(i)(1×10001800), i=1.5

If ‘x’ g of ice is separated from solution 2=(1.8)(1.5)(1×10001800x), 1800x=1350, x=450g

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