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Q.

An amplitude modulated wave is modulated to 50% what is the saving in power if carrier as well as one of the side bands are suppressed

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a

80.2 %

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20.2 %

answer is A.

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Detailed Solution

$P_{t} = P_{C} + P_{S B} P_{C} = \frac{A c^{2}}{2 R} P_{S B} = P_{L s b} + P_{U S B} P_{S B} = \frac{μ^{2} A c^{2}}{4 R}$

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