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$An angle θ through which a pulley turns with time ' t' is completed by$ $θ = t^{2} + 3 t - 5 sq.cms / \min . Then the angular velocity for t = 5 \sec$

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$5^{c} / \sec$

$13^{c} / \sec$

$23^{c} / \sec$

$35^{c} / \sec$

answer is B.

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Detailed Solution

$\begin{array}{l} θ = t^{2} + 3 t - 5, \\ \frac{d θ}{d t} = 2 t + 3 \Rightarrow {(\frac{d θ}{d t})}_{t = 5 \sec} = 2 (5) + 3 = 13 \\ Hence option (B) is correct. \end{array}$

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