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Q.

An ant is at a corner of a cubical room of side $a$ . The ant can move with a constant speed $u$ . The minimum time taken to reach the farthest corner of the cube is

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a

$\frac{\sqrt{3} a}{u}$

b

$\frac{(\sqrt{2} + 1) a}{u}$

c

$\frac{\sqrt{5} a}{u}$

d

$\frac{3 a}{u}$

answer is C.

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Detailed Solution

Question Image

$P Q R = \sqrt{5} a t = \frac{\sqrt{5} a}{u}$ $\sin c e P Q = Q R = \frac{a \sqrt{5}}{2}$

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