An aqueous $K C l$ solution of density 1.20g $m L^{- 1}$ has a molality of 3.30 mol $k g^{- 1}$ .
The molarity of the solution in mol $L^{- 1}$ is_________. (Nearest integer )
$[M o l a r m a s s o f K C l = 74.5]$

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answer is 3.

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Detailed Solution

$3.30 \times 74.5 g K C l$ present with 1000 g water
Mass of solution $= 1245.85 g;$
Volume of solution $= 1038.2 m o l$
Molarity $= \frac{3.3}{1038.2} \times 1000 = 3.17$

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