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Q.

An aqueous solution containing 6.5 g of NaCl of 90% purity was subjected to electrolysis. After the complete electrolysis, the solution was evaporated to get solid NaOH. The volume of 1 M acetic acid required to neutralise NaOH obtained above is

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Detailed Solution

Weight of pure NaCl = 6.5 x 0.9 = 5.85 g

 Number of equivalence of NaCl=5.8558.5=0.1

Number of equivalence of NaOH obtained = 0.1

Volume of I M acetic acid required for the neutralisation of NaOH=0.1×10001=100 cm3

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