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Q.

An aqueous solution containing ‘m’ moles of non-volatile non-electrolyte solute freezes at 0.1860C.  The elevation in the boiling point of the same aqueous solution (K=1.86K  kg  mol1,K=0.512K  kg  mol1)  would be
 

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a

0.0512

b

0.186

c

0.512/1.86

d

0.512

answer is C.

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Detailed Solution

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ΔTb=i×kb×M

TbTf=KbKf

Tb=0.512×0.1861.86=0.0512

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