An aqueous solution is made by dissolving glucose $(C_{6} H_{12} O_{6})$ and urea $({NH}_{2} {CONH}_{2})$ in water. Mole ratio of glucose and water is $1 : 10$ . If the masses of glucose and urea are in 3:1 ratio, then correct statement(s) regarding the solution is/are :

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Infinity Learn · Accepted Answer

Mass      Ratio   Glucose                    Urea  $$3$$:$$1$$    Molar Ratio $$=$$ $$3180$$ $$160$$                                   $$1$$           $$1Given$$ molar ratio of glucose and $$H2O=1$$:$$10Hence$$ molar ratio of all three Glucose  Urea  $$H2O1$$: $$1$$:    $$10$$  Mole fraction of glucose $$=nglucose$$ nglucose $$+nurea$$ $$+nH2O=11+1+10=112And$$ mglucose $$=murea$$ $$=1180$$×$$1000$$

An aqueous solution is made by dissolving glucose $(C_{6} H_{12} O_{6})$ and urea $({NH}_{2} {CONH}_{2})$ in water. Mole ratio of glucose and water is $1 : 10$ . If the masses of glucose and urea are in 3:1 ratio, then correct statement(s) regarding the solution is/are :

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An aqueous solution is made by dissolving glucose C6H12O6 and urea NH2CONH2 in water. Mole ratio of glucose and water is 1:10. If the masses of glucose and urea are in 3:1 ratio, then correct statement(s) regarding the solution is/are :

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An aqueous solution is made by dissolving glucose $(C_{6} H_{12} O_{6})$ and urea $({NH}_{2} {CONH}_{2})$ in water. Mole ratio of glucose and water is $1 : 10$ . If the masses of glucose and urea are in 3:1 ratio, then correct statement(s) regarding the solution is/are :