An aqueous solution is made by dissolving glucose $\left({\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6\right)$ and urea $\left({\mathrm{NH}}_2{\mathrm{CONH}}_2\right)$ in water. Mole ratio of glucose and water is $1:10$. If the masses of glucose and urea are in 3:1 ratio, then correct statement(s) regarding the solution is/are :

 

$\begin{array}{ccc}\text{ Mass }& \text{ Ratio }& \\ \text{ Glucose }& \text{ Urea }& \\ 3& :& 1 \end{array}$

$$\begin{gathered} \text{ Molar Ratio }=\frac{3}{180}\frac{1}{60} \\ 1 1 \end{gathered}$$

Given molar ratio of glucose and ${\mathrm{H}}_2\mathrm{O}=1:10$

Hence molar ratio of all three

$\begin{array}{cccc}\text{ Glucose }& \text{ Urea }& & {\mathrm{H}}_2\mathrm{O}\\ 1& :1& : 10& \end{array}$

$\begin{array}{r}\text{ Mole fraction of glucose }=\frac{n_{\text{glucose }}}{n_{\text{glucose }}+n_{\text{urea }}+n_{{\mathrm{H}}_2\mathrm{O}}}\\ =\frac{1}{1+1+10}=\frac{1}{12}\end{array}$

And $m_{\text{glucose }}=m_{\text{urea }}=\frac{1}{180}\times 1000$