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An aqueous solution is made by dissolving glucose $(C_{6} H_{12} O_{6})$ and urea $({NH}_{2} {CONH}_{2})$ in water. Mole ratio of glucose and water is $1 : 10$ . If the masses of glucose and urea are in 3:1 ratio, then correct statement(s) regarding the solution is/are :

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The mole fraction of glucose in the solution is

\frac{1}{11}

The mole fraction of urea in the solution is

\frac{1}{12}

Molality of glucose in the solution is

\frac{25}{6}

Molality of urea in the solution is

\frac{50}{9}

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detailed solution

Correct option is B

$\begin{array}{ccc} Mass & Ratio \\ Glucose & Urea \\ 3 & : & 1 \end{array}$

$Molar Ratio = \frac{3}{180} \frac{1}{60} 1 1$

Given molar ratio of glucose and $H_{2} O = 1 : 10$

Hence molar ratio of all three

$\begin{array}{cccc} Glucose & Urea & H_{2} O \\ 1 & : 1 & : 10 \end{array}$

$\begin{aligned} Mole fraction of glucose = \frac{n_{glucose}}{n_{glucose} + n_{urea} + n_{H_{2} O}} \\ = \frac{1}{1 + 1 + 10} = \frac{1}{12} \end{aligned}$

And $m_{glucose} = m_{urea} = \frac{1}{180} \times 1000$

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An aqueous solution is made by dissolving glucose C6H12O6 and urea NH2CONH2 in water. Mole ratio of glucose and water is 1:10. If the masses of glucose and urea are in 3:1 ratio, then correct statement(s) regarding the solution is/are :

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Ready to Test Your Skills?

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An aqueous solution is made by dissolving glucose $(C_{6} H_{12} O_{6})$ and urea $({NH}_{2} {CONH}_{2})$ in water. Mole ratio of glucose and water is $1 : 10$ . If the masses of glucose and urea are in 3:1 ratio, then correct statement(s) regarding the solution is/are :