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Q.

An aqueous solution of a salt ${MX}_{2}$ at certain temperature has a van 't Hoff factor of 2. The degree of dissociation for this solution of the salt is

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a

0.50

b

0.67

c

0.80

d

0.33

answer is A.

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Detailed Solution

We have

${MX}_{2} ⇋ M^{2 +} + 2 X^{-} m (1 - α) mα 2 mα$

Total molality in the solution $= m (1 + 2 α)$

Hence $\frac{m (1 + 2 α)}{m} = 2$

This gives $α = 0.50$

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