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An aqueous solution of a weak monobasic acid containing 0.1 g in 21.7 g of water freezes at 272.813 K. If the value of $K_{f}$ for water is 1.86 K/m, what is the molecular mass of the monobasic acid

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55 g/mol

25.6 g/mol

50 g/mol

46 g/mol

answer is D.

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Detailed Solution

$m = \frac{K_{f} \times w \times 1000}{{ΔT}_{f} \times W} m = \frac{1.86 \times 0.1 \times 1000}{0.337 \times 21.7} = 25.6 gm / mol$

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