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An aqueous solution of ${CH}_{3} COOH$ has a pH= 3 and acid dissociation constant of ${CH}_{3} COOH$ is $10^{- 5}$ . What will be the concentration of acid taken initially?

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0.1 M

0.11 M

0.09 M

0.101 M

answer is D.

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Detailed Solution

$[H^{+}] = \sqrt{k_{a} \cdot c}$

However, $α$ has been neglected as compared to 1. Use,

$10^{- 5} = \frac{c \times α^{2}}{1 - α}$ and $c \cdot α = 10^{- 3}$

$\Rightarrow c = 0.101 M$

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