An aqueous solution of CoCl2 on addition of excess of concentrated HCl turns blue due to formation of

An aqueous solution of CoCl2 on addition of excess of concentrated HCl turns blue due to formations of[CoCl4]2−. In [CoCl4]2−, the central Co(II) ion has [Ar]3d7 electronic configuration.In the tetrahedral field, it has 3 unpaired electrons. It results in a blue color.

An aqueous solution of CoCl2 on addition of excess of concentrated HCl turns blue due to formation of

An aqueous solution of CoCl2 on addition of excess of concentrated HCl turns blue due to formations of[CoCl4]2−. In [CoCl4]2−, the central Co(II) ion has [Ar]3d7 electronic configuration.In the tetrahedral field, it has 3 unpaired electrons. It results in a blue color.

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An aqueous solution of CoCl₂ on addition of excess of concentrated HCl turns blue due to formation of

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[Co(H₂O)₄Cl₂]

[Co(H₂O)₂Cl₄]^2–

[Co(H₂O)₂Cl₂]

[CoCl₄]^2–

answer is C.

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Detailed Solution

An aqueous solution of CoCl₂ on addition of excess of concentrated HCl turns blue due to formations of
[CoCl₄]²⁻. In [CoCl₄]²⁻, the central Co(II) ion has [Ar]3d⁷ electronic configuration.
In the tetrahedral field, it has 3 unpaired electrons. It results in a blue color.