An aqueous solution of colourless metal sulphate M, gives a white precipitate with $N H_{4} O H .$ This was soluble in excess of $N H_{4} O H .$ On passing $H_{2} S$ gas through this solution a white precipitate is formed. The metal M in the salt is :

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answer is D.

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Detailed Solution

An aqueous solution of colourless zinc sulphate gives white ppt of $Zn (OH)_{2}$ with ${NH}_{4} OH$

${ZnSOO}_{4} + 2 {NH}_{4} OH \to zn (OH)_{2} + {({NH}_{4})}_{2} {SO}_{4}$

It was soluble in excess of ${NH}_{4} OH$ to form Ammonium Zincate ${({NH}_{4})}_{2} {ZnO}_{2}$

$Zn (OH)_{2} + 2 {NH}_{4} OH \to {({NH}_{4})}_{2} {ZnO}_{2} + 2 H_{2} O$

On passing $H_{2} S$ through the solution a white ppt of ZnS is formed.

${({NH}_{4})}_{2} {ZnO}_{2} + H_{2} S \to ZnS + 2 {NH}_{4} OH$

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