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An aqueous solution of glucose boils at $100 . 01^{\circ} C$ . The molal elevation constant for water is 0.5 K $m o l^{- 1}$ kg. The number of glucose molecules in the solution containing 100g water are _____x $10^{21}$

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Detailed Solution

$∵ Δ T = \frac{1000 K_{b}^{1} w}{m W}$
$0.01 = \frac{1000 \times 0.5 \times w}{180 \times 100} \Rightarrow ∴ w = 0.36 g$
$∵$ 180 g glucose contains $6.023 \times 10^{23}$ molecules
$∴$ 0.36g glucose contains $= \frac{6.023 \times 10^{23} \times 0.36}{180} = 1.2 \times 10^{21}$ molecules

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An aqueous solution of glucose boils at 100.01∘C. The molal elevation constant for water is 0.5 K mol-1 kg. The number of glucose molecules in the solution containing 100g water are _____x 1021