An aqueous solution of sodium stearate, C17H35 COONa, becomes a colloidal sol at the concentration of 1.2 × 10–3 M at 25°C. If at this concentration, 2.4 × 1013 colloidal (micelle) particles are present per mm3 , the number of stearate ions in each colloidal particle is : (NA = 6 × 1023)

1 mm3=10-9 m3 1 m3→ 103 litre 10-4 m3→ 10-6 litrenumber of particle=1.2×10-9×NA2.4×1013=12×10-22×6×1023=30

1 mm3=10-9 m3 1 m3→ 103 litre 10-4 m3→ 10-6 litrenumber of particle=1.2×10-9×NA2.4×1013=12×10-22×6×1023=30

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An aqueous solution of sodium stearate, $C_{17} H_{35} COONa$ , becomes a colloidal sol at the concentration of $1.2 \times 10 - 3 M at 25 ° C$ . If at this concentration, $2.4 \times 10^{13}$ colloidal (micelle) particles are present per ${mm}^{3}$ , the number of stearate ions in each colloidal particle is : $(NA = 6 \times 10^{23})$

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$1 {mm}^{3} = 10^{- 9} m^{3} 1 m^{3} \overset{}{\to} 10^{3} litre 10^{- 4} m^{3} \overset{}{\to} 10^{- 6} litre$

number of particle $= \frac{1.2 \times 10^{- 9} \times N_{A}}{2.4 \times 10^{13}}$

$= \frac{1}{2} \times 10^{- 22} \times 6 \times 10^{23} = 30$

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