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An aqueous solution of $H_{2} O$ is labelled as 28.375 V $H_{2} O_{2}$ and the density of solution is 1.25 gm/ml. Then the correct option will be :

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Molality of solution is 2.15 m

Molality will be 2 m

Molarity of $H_{2} O_{2}$ is 1.25 m

Molality will be 5 m

answer is C.

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Detailed Solution

Molarity,

$M = \frac{28 .375}{11 .35} = 2 .5$

1000 mL of solution contains 2.5 mole $H_{2} O_{2}$

Molarity,

$m = \frac{2 .5}{1250 - 85} \times 1000$

$= 2 .15 m$

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