An archer stretches a bow to release an arrow to hit the target at a distance of $10 m$ . Which of the following is the correct energy conversion that takes place here?

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Muscular energy of the archer → Kinetic energy of the bow

Muscular energy of the archer → Kinetic energy of the arrow

Muscular energy of the archer → Potential energy of the bow → Kinetic energy of the arrow

Potential energy of the arrow → Kinetic energy of the arrow

answer is C.

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Detailed Solution

An archer stretches a bow to release an arrow to hit the target at a distance of

10 m

. Muscular energy of the archer → Potential energy of the bow → Kinetic energy of the arrow is the correct energy conversion that takes place here.
Kinetic energy:
"Kinetic energy is the energy associated with the movement of objects. Kinetic energy is directly proportional to the mass of the object (

m

) and the square of its velocity (

v

).”

K . E . = \frac{1}{2} m v^{2}

Potential energy:
“Potential energy is the energy that is stored in an object due to its position or configuration.”

W = mgh

Where

m

is the mass,

g

is the acceleration and

h

is the height.
When an arrow is drawn back by a bow, the work done in stretching the bowstring gets stored at potential energy in the bow. This potential energy of the bow is transformed into kinetic energy when the bowstring is released, giving kinetic energy to the arrow.
Archer does the work in stretching the bowstring. He uses his muscular energy to store potential energy in the bow. When the bowstring is released its potential energy is transferred to the arrow in the form of Kinetic energy.
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